Issue44344

Created on **2021-06-08 04:13** by **eyadams**, last changed **2021-06-09 08:52** by **steven.daprano**.

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msg395305 - (view) | Author: Erik Y. Adams (eyadams) | Date: 2021-06-08 04:13 | |

https://docs.python.org/3/library/functions.html#pow The built-in pow() function will return a complex number if the base is negative and the exponent is a float between 0 and 1. For example, the value returned by `pow(-1, 1.0/3)` is `(1.0000000000000002+1.7320508075688772j)` The answer is mathematically correct, but `-2.0` is also mathematically correct. There is nothing in the documentation currently to suggest that a complex number might be returned; in fact, given the statement "[with] mixed operand types, the coercion rules for binary arithmetic operators apply", one might reasonably expect `-2.0` as the answer. I suggest the following sentences be added to the end of the second paragraph: "If `base` is negative and the `exp` is a `float` between 0 and 1, a complex number will be returned. For example, `pow(-8, 1.0/3)` will return `(1.0000000000000002+1.7320508075688772j)`, and not `-2.0.`" |
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msg395308 - (view) | Author: Dennis Sweeney (Dennis Sweeney) * | Date: 2021-06-08 05:56 | |

For some prior art, https://www.wolframalpha.com/input/?i=%28-8%29+%5E+%281%2F3%29 says it defaults to using "the principal root" over "the real-valued root" Also, I think the relevant property is that the exponent is not an integer; being between 0 and 1 is irrelevant: >>> pow(-8, 4/3) (-8.000000000000005-13.856406460551014j) Maybe the tweak could be something like "Note that using a negative base with a non-integer exponent will return the principal complex exponent value, even if a different real value exists." |
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msg395339 - (view) | Author: Mark Dickinson (mark.dickinson) * | Date: 2021-06-08 16:20 | |

[Dennis] > I think the relevant property is that the exponent is not an integer Yep: the delegation to complex pow kicks in after handling infinities and nans, and only for strictly negative base (-0.0 doesn't count as negative for this purpose) and non-integral exponent. Here's the relevant code: https://github.com/python/cpython/blob/257e400a19b34c7da6e2aa500d80b54e4c4dbf6f/Objects/floatobject.c#L773-L782 To avoid confusion, we should probably not mention fractions like `1/3` and `4/3` as example exponents in the documentation, since those hit the What-You-See-Is-Not-What-You-Get nature of binary floating-point. Mathematically, `z^(1/3)` is a very different thing from `z^(6004799503160661/18014398509481984)` for a negative real number `z`, and the latter is what's _actually_ being computed with `z**(1/3)`. The advantage of the principal branch approach is that it's continuous in the exponent, so that `z^(1/3)` and `z^(6004799503160661/18014398509481984)` only differ by a tiny amount. |

History | |||
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Date | User | Action | Args |

2021-06-09 08:52:14 | steven.daprano | set | nosy:
+ steven.daprano |

2021-06-08 16:20:04 | mark.dickinson | set | nosy:
+ mark.dickinson messages: + msg395339 |

2021-06-08 05:56:47 | Dennis Sweeney | set | nosy:
+ Dennis Sweeney messages: + msg395308 |

2021-06-08 04:13:36 | eyadams | create |