I have printed min('Infinity') and min('infinity') . 
Both are printing different characters. 
In first case , It's printing 'I' and in second case, it's printing 
'F'

when I try to print min('Infinity') and min (InFinity). In first case, it's printing 'I' and in second case it's printing 'F'. Is this issue or working as Is ?

Here min uses the ASCII value of the letters for comparison. So for 'Infinity' 'I' (73) has the lowest value and for 'inFinity' 'F' (70) has the lowest value as seen below.

>>> list(map(lambda c: (c, ord(c)), 'Infinity'))
[('I', 73), ('n', 110), ('f', 102), ('i', 105), ('n', 110), ('i', 105), ('t', 116), ('y', 121)]
>>> list(map(lambda c: (c, ord(c)), 'inFinity'))
[('i', 105), ('n', 110), ('F', 70), ('i', 105), ('n', 110), ('i', 105), ('t', 116), ('y', 121)]

This has nothing in particular do with `min()`.  As strings, 'I' < 'i', and 'F' < 'I'.  For example,

>>> 'I' < 'i'
True

>>> sorted("InFinity")
['F', 'I', 'i', 'i', 'n', 'n', 't', 'y']

That's all working as intended and as documented, so I'm closing this report.

Hello Tim,

Thanks for your quick response.

Also, THE min("Infinity") is priniting "I".  Practically, the minimum
value is "e" right ?

Regards,
Pavan Uppalanchu

On Mon, Sep 2, 2019 at 11:31 PM Tim Peters <report@bugs.python.org> wrote:
>
>
> Tim Peters <tim@python.org> added the comment:
>
> This has nothing in particular do with `min()`.  As strings, 'I' < 'i', and 'F' < 'I'.  For example,
>
> >>> 'I' < 'i'
> True
>
> >>> sorted("InFinity")
> ['F', 'I', 'i', 'i', 'n', 'n', 't', 'y']
>
> That's all working as intended and as documented, so I'm closing this report.
>
> ----------
> nosy: +tim.peters -xtreak
> resolution:  -> not a bug
> stage:  -> resolved
> status: open -> closed
>
> _______________________________________
> Python tracker <report@bugs.python.org>
> <https://bugs.python.org/issue38012>
> _______________________________________

Hello Karthikeyan,

Thank you very much for your valuable explanation.

Regards,
Pavan Uppalanchu

On Mon, Sep 2, 2019 at 11:28 PM Karthikeyan Singaravelan
<report@bugs.python.org> wrote:
>
>
> Karthikeyan Singaravelan <tir.karthi@gmail.com> added the comment:
>
> Here min uses the ASCII value of the letters for comparison. So for 'Infinity' 'I' (73) has the lowest value and for 'inFinity' 'F' (70) has the lowest value as seen below.
>
> >>> list(map(lambda c: (c, ord(c)), 'Infinity'))
> [('I', 73), ('n', 110), ('f', 102), ('i', 105), ('n', 110), ('i', 105), ('t', 116), ('y', 121)]
> >>> list(map(lambda c: (c, ord(c)), 'inFinity'))
> [('i', 105), ('n', 110), ('F', 70), ('i', 105), ('n', 110), ('i', 105), ('t', 116), ('y', 121)]
>
> ----------
> nosy: +xtreak
>
> _______________________________________
> Python tracker <report@bugs.python.org>
> <https://bugs.python.org/issue38012>
> _______________________________________

> Also, THE min("Infinity") is priniting "I".  Practically,
> the minimum value is "e" right ?

Sorry, I have no idea what "practically" means to you.  It's just a fact that all uppercase ASCII letters compare less than all lowercase ASCII letters:

>>> 'I' < 'e'
True
>>> 'Z' < 'a'
True

This isn't just Python - it's an industry-wide standard.  Look at any reference for the ASCII character set; for example, here:

http://www.asciitable.com/

Try posting about what you're trying to accomplish on the Python mailing list?  The issue tracker isn't the right place for tutorials.