If a variable 'x' exists in the global or local scope, and a function (also defined in the same scope as 'x', or lower) refers only to a member named 'x' of an object, inspect.getclosurevars will include a reference to the variable, rather than the member.

Okay, that's kind of confusing to describe, so here's a small example in code form:

import inspect

class Foo:
    x = int()

x = 1
f = Foo()
assert(f.x != x)

func = lambda: f.x == 0
assert(func())

cv = inspect.getclosurevars(func)
assert(cv.globals['f'] == f)
assert(cv.globals.get('x') != x) # <--- Assertion fails


It is expected that 'x' would not exist in cv.globals, since func does not refer to it. Also, there should be a 'f.x' included somewhere in the ClosureVariables object returned.

Reproduced on 3.11.

Why is expected that 'x' would not exist in cv.globals? I think it works normally, you can see `x` in `func.__globals__`.

If you change the class member 'x' to a different name like 'y', then cv
doesn't include 'x', but does include an unbound 'y'.

In both cases, the function isn't referring to a global variable, just the
class member of that name. Besides the function itself, no other globals
are included in cv.globals.

On Sat, Dec 18, 2021 at 10:34 AM hongweipeng <report@bugs.python.org> wrote:

>
> hongweipeng <hongweichen8888@sina.com> added the comment:
>
> Why is expected that 'x' would not exist in cv.globals? I think it works
> normally, you can see `x` in `func.__globals__`.
>
> ----------
> nosy: +hongweipeng
>
> _______________________________________
> Python tracker <report@bugs.python.org>
> <https://bugs.python.org/issue26577>
> _______________________________________
>