Message142503
You can easily get the fractional day value using existing functionality:
>>> from datetime import *
>>> (datetime(2011,8,15,18,30) - datetime(2011,8,13,12,0)) / timedelta(1)
2.2708333333333335
>>> (datetime(2011,8,15,18,30) - datetime(1970,1,1)) / timedelta(1)
15201.770833333334
In some sense this request is a duplicate of issue2736. |
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Date |
User |
Action |
Args |
2011-08-19 22:53:11 | belopolsky | set | recipients:
+ belopolsky, daniel.urban, Miguel.de.Val.Borro |
2011-08-19 22:53:11 | belopolsky | set | messageid: <1313794391.27.0.770303916066.issue12772@psf.upfronthosting.co.za> |
2011-08-19 22:53:10 | belopolsky | link | issue12772 messages |
2011-08-19 22:53:10 | belopolsky | create | |
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