It would be useful to have a fractional day method in datetime.datetime
that returns a float object calculated from the day, hour, minute, second, and microseconds. Fractional days in UTC are often used in science, in particular to record astronomical observations.

You can easily get the fractional day value using existing functionality:


>>> from datetime import *
>>> (datetime(2011,8,15,18,30) -  datetime(2011,8,13,12,0)) / timedelta(1)
2.2708333333333335
>>> (datetime(2011,8,15,18,30) -  datetime(1970,1,1)) / timedelta(1)
15201.770833333334

In some sense this request is a duplicate of issue2736.

Thanks, I need the fractional day added to the ordinal day of the month. Using the timedelta division it would be:

>>> from __future__ import division
>>> dt = datetime.datetime(2008, 5, 8, 13, 35, 41, 567777)
>>> dt.day + (dt-datetime.datetime(dt.year, dt.month, dt.day))/datetime.timedelta(1)
8.566453330752315

Then it simply becomes a one line function so I'm closing this ticket.