The operator override dunder methods, like `__add__`, are described in
the “Data model” docs here:
<https://docs.python.org/3.10/reference/datamodel.html#object.__add__>

Those docs say:

> For instance, to evaluate the expression `x + y`, where `x` is an
> instance of a class that has an `__add__()` method, `x.__add__(y)` is
> called.

But this is not correct: `x + y` always uses `type(x).__add__`, which
may be different from `x.__add__` if `__add__` has been set directly on
the instance.

Demonstration:

```
class C:
    def __add__(self, other):
        return "from class"


c = C()
print(c + c)  # prints "from class"

c.__add__ = lambda other: "from instance"
print(c.__add__(c))  # prints "from instance"
print(type(c).__add__(c, c))  # prints "from class"

print(c + c)  # prints "from class"!
```

The same issue appears in the reversed operator dunder (`__radd__`,
et al.) docs below.

I have a patch that I can submit as a PR; just need a bpo number.

New changeset 80f33f266b4ad5925a3e58ea3a54ae139a6b6f0e by William Chargin in branch 'main':
bpo-41706: Fix special method invocation docs to mention using type() (GH-22084)
https://github.com/python/cpython/commit/80f33f266b4ad5925a3e58ea3a54ae139a6b6f0e