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Author mark.dickinson
Recipients mark.dickinson, ms
Date 2008-08-04.23:07:06
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A cheap trick would be to use the identity

  expm1(x) = 2*exp(x/2)*sinh(x/2)

This could also be used in Python as a
workaround, for now.  But I agree that
expm1 should go into the math library.
Date User Action Args
2008-08-04 23:07:07mark.dickinsonsetrecipients: + mark.dickinson, ms
2008-08-04 23:07:07mark.dickinsonsetmessageid: <>
2008-08-04 23:07:06mark.dickinsonlinkissue3501 messages
2008-08-04 23:07:06mark.dickinsoncreate