Message357025
It's not clear what you're asking for here. Your example works, though the contents of `a` and `c` will each be an arbitrary member of S and `b` the rest of the members of S and you have no guarantee of what you'll get. If you want to be sure of what each name will be attached to, just do `a, *b, c = sorted(S)`. |
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Date |
User |
Action |
Args |
2019-11-20 03:53:49 | zach.ware | set | recipients:
+ zach.ware, Ylem |
2019-11-20 03:53:49 | zach.ware | set | messageid: <1574222029.2.0.0309593302797.issue38855@roundup.psfhosted.org> |
2019-11-20 03:53:49 | zach.ware | link | issue38855 messages |
2019-11-20 03:53:49 | zach.ware | create | |
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