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Author HardikPatel
Recipients HardikPatel, ned.deily, ronaldoussoren
Date 2019-03-21.22:59:11
SpamBayes Score -1.0
Marked as misclassified Yes
Message-id <1553209151.69.0.362760019961.issue36393@roundup.psfhosted.org>
In-reply-to
Content
I have created function "listappend():"with two arguments.Function can append list value with each function call and return updated value. I am trying to store this updated value into variable which I can but when I call listappend() to update it changes the stored variable value every time when I call a function.

You can see in below given example, list value is [10,20,30] and I have stored with value 40 in varible x.
so now x is [10,20,30,40]. I called function with new list value with [50] now it become [10,20,30,40,50]            
and the value of x is replaced with new value.  Even if you store x into a new variable and call listappend() again with new value then it will replace the value of new variable.  
 
>>> def listappend(a,list=[]):  
...     list.append(a)
...     return list
... 
>>> listappend(10) 
[10]
>>> listappend(20) 
[10, 20]
>>> listappend(30) 
[10, 20, 30]
>>> x = listappend(40) 
>>> print(x)
[10, 20, 30, 40]
>>> y = listappend(50) 
>>> print(y)
[10, 20, 30, 40, 50]
>>> z = listappend(60) 
>>> print(z)
[10, 20, 30, 40, 50, 60]
>>> print(x)                  
[10, 20, 30, 40, 50, 60]
>>> print(y)              
[10, 20, 30, 40, 50, 60]
>>> print(z)
[10, 20, 30, 40, 50, 60]
>>>
History
Date User Action Args
2019-03-21 22:59:11HardikPatelsetrecipients: + HardikPatel, ronaldoussoren, ned.deily
2019-03-21 22:59:11HardikPatelsetmessageid: <1553209151.69.0.362760019961.issue36393@roundup.psfhosted.org>
2019-03-21 22:59:11HardikPatellinkissue36393 messages
2019-03-21 22:59:11HardikPatelcreate