Setting __hash__ to None doesn't do what you think. It doesn't prevent __hash__ from being called by hash(), instead it produces a TypeError.

>>> class A: __hash__ = None
... 
>>> hash(A())
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unhashable type: 'A'

Actually the effect of special casing __hash__ is not raising a TypeError, but raising a TypeError with better error message. A TypeError was already raised before if set __hash__ to a non-callable. In 2.7:

>>> class A: __hash__ = None
... 
>>> hash(A())
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'NoneType' object is not callable


If you want to prevent an inherited __init__ from being called by types's __call__, you can define an __init__ with an empty body.

    def __init__(self, *args, **kwargs):
        pass