Message221600
While searching for a way to work around the breakage of the Schwartzian transform in Python 3 (and the resulting awkwardness if you wish to use heapq or bisect, which do not yet have a key argument), I thought of the good old IEEE-754 NaN. Unfortunately, that shouldn't work since lexicographical comparisons shouldn't stop for something comparing False all the time. Nevertheless:
>>> (1, float("nan"), A()) < (1, float("nan"), A())
False
>>> (0, float("nan"), A()) < (1, float("nan"), A())
True
Instead of as in
>>> nan = float("nan")
>>> (1, nan, A()) < (1, nan, A())
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: unorderable types: A() < A()
(As a side note, PyPy3 does not have this bug.) |
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Date |
User |
Action |
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2014-06-26 08:23:29 | Electro | set | recipients:
+ Electro |
2014-06-26 08:23:29 | Electro | set | messageid: <1403771009.56.0.175285571524.issue21873@psf.upfronthosting.co.za> |
2014-06-26 08:23:29 | Electro | link | issue21873 messages |
2014-06-26 08:23:28 | Electro | create | |
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