Take a fonction with a parameter and  *args
def foo(bar, args*)
  pass

then call it like this
myargs = [1, 2, 3, 4, 5]
foo(bar=1, *myargs)

The call produce this error : 
TypeError: foo() got multiple values for keyword argument 'bar'

Sould the error be more like : 
SyntaxError: non-keyword arg after keyword arg

the same error if foo was called like this : 
foo(bar=1, myargs)
or
foo(bar=1, 1, 2, 3, 4, 5)

It's a weird error even it reverse order:

>>> def f(foo, *args):
...     pass
...
>>> f(*(1, 2, 3), foo=4)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: f() got multiple values for keyword argument 'foo'

The reverse, f(*(1, 2, 3), foo=4), is consistent with 
f(1,2,3, foo=4)
who also gave 
TypeError: f() got multiple values for keyword argument 'foo'

Which is consistent with the tutorial
http://docs.python.org/tutorial/controlflow.html#keyword-arguments

def parrot(voltage, state='a stiff', action='voom', type='Norwegian Blue'):
...
but the following calls would all be invalid:
parrot(voltage=5.0, 'dead')  # non-keyword argument following keyword
parrot(110, voltage=220)     # duplicate value for argument

As covered in http://docs.python.org/dev/reference/expressions.html#calls, this is how function calls are bound.