Message316184
The behavior of os.path.join() regarding path separators does not match the documentation. This affects Python 3.6, and goes back to at least Python 2.7.
From the documenation:
"The return value is the concatenation of path and any members of *paths with exactly one directory separator (os.sep) following each non-empty part except the last, meaning that the result will only end in a separator if the last part is empty."
To me, this means that join will remove extraneous separators from the path, and that the only way to produce a trailing separator is to use join "" as the final path segment.
I expect `os.path.join("/abc//", "def/")` to produce the string "/abc/def" based on the documentation, but what it actually produces is "abc//def/". |
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Date |
User |
Action |
Args |
2018-05-04 18:39:06 | Michael Klatt | set | recipients:
+ Michael Klatt, docs@python |
2018-05-04 18:39:06 | Michael Klatt | set | messageid: <1525459146.45.0.682650639539.issue33426@psf.upfronthosting.co.za> |
2018-05-04 18:39:06 | Michael Klatt | link | issue33426 messages |
2018-05-04 18:39:06 | Michael Klatt | create | |
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