Thanks a lot David

>Четверг, 24 августа 2017, 18:42 +04:00 от "R. David Murray" <report@bugs.python.org>:
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>R. David Murray added the comment:
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>I would phrase that as "check if any of the components of the path are links", at which point one "obvious"[*] answer is "any(x.is_symlink() for x in [*mypath.parents, mypath])".  If the path is absolute, you could use "not (mypath.resolve() == mypath)".
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>[*] I put that in quotes because it is only obvious once you have a non-trivial amount of experience with programming in Python.
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