Message282623
Run the following script with Python 3.6.0rc1:
class O:
pass
o = O()
for n in range(20):
print(n)
o.x = 42
o.__dict__.pop('x', None)
You can observe the memory usage of the Python process growing exponentially.
E.g. in bash:
ulimit -v 1000000 # don't push other processes into swap please
python3.6 break.py
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Traceback (most recent call last):
File "break.py", line 7, in <module>
o.x = 42
MemoryError |
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Date |
User |
Action |
Args |
2016-12-07 14:47:11 | mgedmin | set | recipients:
+ mgedmin |
2016-12-07 14:47:11 | mgedmin | set | messageid: <1481122031.58.0.509371094394.issue28894@psf.upfronthosting.co.za> |
2016-12-07 14:47:11 | mgedmin | link | issue28894 messages |
2016-12-07 14:47:11 | mgedmin | create | |
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