Message273133
It seems perfectly logical and consistent to me. {4} is a repeat count, as is *. You get the same error if you do 'a?*', and the same bypass if you do '(a?)*' (though I haven't tested if that does anything useful :). You don't need the ?:, as far as I can tell, you just need to have the * modifying a group, making the group the "preceding regular expression". |
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Date |
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Action |
Args |
2016-08-19 15:03:59 | r.david.murray | set | recipients:
+ r.david.murray, ezio.melotti, mrabarnett, martin.panter |
2016-08-19 15:03:59 | r.david.murray | set | messageid: <1471619039.65.0.0624282048448.issue27800@psf.upfronthosting.co.za> |
2016-08-19 15:03:59 | r.david.murray | link | issue27800 messages |
2016-08-19 15:03:59 | r.david.murray | create | |
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