Message235196
It may be written simpler:
d = defaultdict(factory)
for i in constants:
d[i]
or
d = defaultdict(factory, {i: factory() for i in constants})
I'm inclined to reject this proposition. It serves very special use case. |
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Date |
User |
Action |
Args |
2015-02-01 18:53:22 | serhiy.storchaka | set | recipients:
+ serhiy.storchaka, rhettinger, SilentGhost, justanr |
2015-02-01 18:53:22 | serhiy.storchaka | set | messageid: <1422816802.24.0.357754012998.issue23372@psf.upfronthosting.co.za> |
2015-02-01 18:53:22 | serhiy.storchaka | link | issue23372 messages |
2015-02-01 18:53:22 | serhiy.storchaka | create | |
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