Message190817
Reproduction:
Python 2.7.4 (default, Apr 19 2013, 18:28:01)
[GCC 4.7.3] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import struct
>>> struct.pack('!L', 0x01020304)
'\x01\x02\x03\x04'
>>> struct.pack('>L', 0x01020304)
'\x01\x02\x03\x04'
>>> struct.pack('<L', 0x01020304)
'\x04\x03\x02\x01'
>>> struct.pack('L', 0x01020304)
'\x04\x03\x02\x01\x00\x00\x00\x00' ### WAT??? ###
>>>
As far as I see at the source code (http://hg.python.org/releasing/2.7.4/file/9290822f2280/Modules/_struct.c#l703), sizeof(long) is used as the size of 'L', which is equal to 8 at 64bit Linux...
The problem is that the results of packing with 'L' returns 8 bytes,
instead of 4 - as was expected from the documentation... |
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Date |
User |
Action |
Args |
2013-06-08 19:22:48 | rz | set | recipients:
+ rz |
2013-06-08 19:22:48 | rz | set | messageid: <1370719368.01.0.165210926264.issue18169@psf.upfronthosting.co.za> |
2013-06-08 19:22:47 | rz | link | issue18169 messages |
2013-06-08 19:22:47 | rz | create | |
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