If we run 2to3 on the following code:

s = b' '
print s[0] == s

we end up with this:

s = b' '
print(s[0] == s)

However, the first code, under python2 prints True while the converted code, under python3 prints False.

Shouldn't 2to3 convert this code to:

s = b' '
print s[0:1] == s

instead?