Message102120
Background:
building a screen using Tkinter based on information from a database to let user take action on the database rows. I don't know how many rows there will be, so I'm storing the widgets in arrays for each column.
Code:
for row in getDBrows():
self.buttons.append(Tkinter.Button(self,text='UnLoad it', command=lambda :self.unload(row[0])))
Problem:
When executing the above code, all the buttons have the key to the database table that belongs to the last row. I found a work around -- by moving the call to create the button (containing the lambda) to a separate function and call that function to create the button instead of creating the button directly, the buttons then make their callback with a correct database key.
Workaround:
for row in getDBrows():
self.buttons.append(self.buildbutton(row[0]))
.
.
def buildbutton(self,key):
return Tkinter.Button(self,text='UnLoad it', command=lambda: self.unload(key))
When using the workaround code instead of the original code, the button
for each row has the appropriate key to the database.
Speculation:
It acts like the lambda definitions don't get solidified until the containing block exits; at that time, the lambda definition(s) get locked in with the current value of the variable getting passed into the lambda as a parameter. By moving the lambda call to a different block (separate function), the lambda gets "locked" when that block (function) exits instead of when the containing block (loop) exits. |
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Date |
User |
Action |
Args |
2010-04-01 18:26:02 | alan.hoover | set | recipients:
+ alan.hoover |
2010-04-01 18:26:02 | alan.hoover | set | messageid: <1270146362.25.0.403939205554.issue8283@psf.upfronthosting.co.za> |
2010-04-01 18:26:00 | alan.hoover | link | issue8283 messages |
2010-04-01 18:25:59 | alan.hoover | create | |
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