In python shell, I typed words and got result as follows. It seems that the use of 'r' before a literal string may cause an error that the an odd '\' at the end of literal string blocked the quote.

>>> rb'abc\\\'
SyntaxError: EOL while scanning string literal
>>> rb'abc\\'
b'abc\\\\'
>>> br'abc\\\ '
b'abc\\\\\\ '
>>> br'abc\\\'
SyntaxError: EOL while scanning string literal
>>> r'\\'
'\\\\'
>>> r'\\\'
SyntaxError: EOL while scanning string literal

This isn't a bug, in fact this very behavior is documented within the string docs, please read the last paragraph here:

https://docs.python.org/3/reference/lexical_analysis.html#string-and-bytes-literals

Thanks for comment. Here I got my answer from string docs.

Even in a raw literal, quotes can be escaped with a backslash, but the backslash remains in the result; for example, r"\"" is a valid string literal consisting of two characters: a backslash and a double quote; r"\" is not a valid string literal (even a raw string cannot end in an odd number of backslashes). Specifically, a raw literal cannot end in a single backslash (since the backslash would escape the following quote character). Note also that a single backslash followed by a newline is interpreted as those two characters as part of the literal, not as a line continuation.