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Created on 2015-07-07 18:37 by tomskaczmarek, last changed 2022-04-11 14:58 by admin. This issue is now closed.
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| msg246439 - (view) | Author: (tomskaczmarek) | Date: 2015-07-07 18:37 | |
As I understand operator precedence the expression 1<-1==0 ought to evaluate in the following order: 1<-1 evaluates to False (or 0) then False == 0 ought to evaluate yielding True. However, this evaluates to False in my Python 3.4.3 Shell. (1<-1)==0 evaluates to True |
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| msg246440 - (view) | Author: R. David Murray (r.david.murray) *  |
Date: 2015-07-07 18:42 | |
You missed the sentence just before the table that mentions that comparisons support chaining (see https://docs.python.org/3/reference/expressions.html#not-in). 1<-1==0 is actually equivalent to (1<-1) and (1==0), which is False. |
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| History | |||
|---|---|---|---|
| Date | User | Action | Args |
| 2022-04-11 14:58:18 | admin | set | github: 68774 |
| 2015-07-07 18:42:40 | r.david.murray | set | status: open -> closed nosy: + r.david.murray messages: + msg246440 resolution: not a bug stage: resolved |
| 2015-07-07 18:37:25 | tomskaczmarek | create | |