Message79059
Please forgive me, but I'm really trying to wrap my brain around the
behavior of exec() in Python 3. Here's a quote from the documentation:
"In all cases, if the optional parts are omitted, the code is
executed in the current scope."
This is referring to the optional use of the globals/locals parameters
and seems to indicate that if they're omitted the code executes in the
scope where the exec() appeared.
Yet, this code fails:
def foo():
exec("a = 42")
print(a) # NameError: a
Now, I realize that exec() became a function in Python 3. However,
regardless of that, is it really the intent that exec() not be allowed
to ever modify any local variable of a function? In other words, do I
really have to do this?
def foo():
ldict = locals()
exec("a=42",globals(),ldict)
a = ldict['a']
print(a)
I submitted a bug report about this once before and it was immediately
dismissed.
I would appreciate some greater clarity on this matter this go around.
Specifically, what is the approved way to have exec() modify the local
environment of a function? |
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Date |
User |
Action |
Args |
2009-01-04 14:52:37 | beazley | set | recipients:
+ beazley |
2009-01-04 14:52:37 | beazley | set | messageid: <1231080757.34.0.371299910719.issue4831@psf.upfronthosting.co.za> |
2009-01-04 14:52:36 | beazley | link | issue4831 messages |
2009-01-04 14:52:35 | beazley | create | |
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