I downloaded the current source (2.5.2) and confirmed that (1) python
will build as a framework (for me) and (2) that the problem occurs for
my build, too. I did not build it as a universal binary just in case
that helped but mostly to speed things up.

I then tried to add the --with-pydebug flag to my configure script and
build that way. I used separate build directories for the two builds to
keep the source clean. Unfortunately, make fails with the following
error in that case:

if test ""; then \
        gcc -o Python.framework/Versions/2.5/Python -arch i386 -arch ppc
-dynamiclib \
                -isysroot "" \
                -all_load libpython2.5.a -Wl,-single_module \
                -install_name
/Library/Frameworks/Python.framework/Versions/2.5/Python \
                -compatibility_version 2.5 \
                -current_version 2.5; \
        else \
        /usr/bin/libtool -o Python.framework/Versions/2.5/Python
-dynamic  libpython2.5.a \
                 -lSystem -lSystemStubs -arch_only ppc -install_name
/Library/Frameworks/Python.framework/Versions/2.5/Python
-compatibility_version 2.5 -current_version 2.5 ;\
fi
ld: Undefined symbols:
___eprintf
/usr/bin/libtool: internal link edit command failed
make: *** [Python.framework/Versions/2.5/Python] Error 1

I am guessing that eprintf has something to do with the debug option
because the symbol occurs in the debug version of libpython2.5.a but not
the plain version as far as I can tell. But I'm not sure how to fix it.

I am not even sure I am running the debugger correctly with the existing
version of python. I tried passing "-v -v" and "-d" to python after
reading the man page and that didn't get me any extra information.
Nothing useful-looking, at least. ("-v -v" produced a lot of output
beforehand but not around the point the error occurs.) Is that what you
meant or should I be looking at something else?

I am sorry but I don't know how to augment the source code with printf
and that is such a common term I'm not sure what to google to find
instructions for doing it.