def isplit(text, sep=None, maxsplit=-1):
    """
    A lowmemory-footprint version of:

        iter(text.split(sep, maxsplit))

    Adapted from https://stackoverflow.com/a/9770397
    """

    if maxsplit == 0:
        yield text
    else:
        rsep = re.escape(sep) if sep else r'\s+'
        regex = fr'(?:^|{rsep})((?:(?!{rsep}).)*)'

        for n, p in enumerate(re.finditer(regex, text)):
            if 0 <= maxsplit <= n:
                yield p.string[p.start(1):]
                return
            yield p.group(1)