Author mark.dickinson
Recipients juraj.sukop, mark.dickinson, rhettinger, serhiy.storchaka, stutzbach
Date 2021-01-28.13:57:21
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> the only thing I'm not sure about is whether the final correction in the original `isqrt` is needed

Well, *some* part of the algorithm has to make use of the low-order bits of n. Otherwise we won't be able to distinguish n = 4a**2 + 4a + 1 (whose isqrt is 2a + 1) from 4a**2 + 4a (whose isqrt is 2a).
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