Message376440
This should stay closed as a duplicate.
If you must, reopen of the original 27071, but it was closed for a reason. The majority of respondents voted for the status quo. Each alternative that was considered had its own share of problems.
BTW, it is hyperbolic to call the name "horribly misleading". The method literally runs Counter and checks for equality. The docstring is clear about this:
def assertCountEqual(self, first, second, msg=None):
"""Asserts that two iterables have the same elements, the same number of
times, without regard to order.
self.assertEqual(Counter(list(first)),
Counter(list(second)))
Example:
- [0, 1, 1] and [1, 0, 1] compare equal.
- [0, 0, 1] and [0, 1] compare unequal.
""" |
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Date |
User |
Action |
Args |
2020-09-05 20:02:41 | rhettinger | set | recipients:
+ rhettinger, ammar2, vitaly.krug |
2020-09-05 20:02:41 | rhettinger | set | messageid: <1599336161.88.0.939436877914.issue38240@roundup.psfhosted.org> |
2020-09-05 20:02:41 | rhettinger | link | issue38240 messages |
2020-09-05 20:02:41 | rhettinger | create | |
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