Message372104
```
>>> re.sub('a*', '-', 'a')
'--'
>>> re.sub('a*', '-', 'aa')
'--'
>>> re.sub('a*', '-', 'aaa')
'--'
```
Shouldn't it be returning one dash, not two, since the greedy quantifier will match all the a's? I understand why substituting on 'b' returns '-a-', but shouldn't this constitute only one match? In Python 2.7, it behaves as I expect:
```
>>> re.sub('a*', '-', 'a')
'-'
>>> re.sub('a*', '-', 'aa')
'-'
>>> re.sub('a*', '-', 'aaa')
'-'
```
The original case that led me to this was trying to normalize a path to end in one slash. I used `re.sub('/*$', '/', path)`, but a nonzero number of slashes came out as two. |
|
Date |
User |
Action |
Args |
2020-06-22 17:28:11 | Yujiri | set | recipients:
+ Yujiri, ezio.melotti, mrabarnett |
2020-06-22 17:28:11 | Yujiri | set | messageid: <1592846891.21.0.0506467079294.issue41080@roundup.psfhosted.org> |
2020-06-22 17:28:11 | Yujiri | link | issue41080 messages |
2020-06-22 17:28:11 | Yujiri | create | |
|