Message367587
I reopen the issue.
The following code works on Python 3.8, but fails with SyntaxError on Python 3.9.0a6 with the old and the new parser (see bpo-40431):
clear = "NORMAL"
print(dict(state=clear, bg="#d00" if clear else"#fca"))
Well, the code looks like a typo error... but it worked previously.
Not sure if we should keep the SyntaxError or not. Fixing the code is trivial: see PR 19777 attached to bpo-40431; replace >else"#fca"< with >else "#fca"<.
Note: I first reported the issue to https://bugs.python.org/issue40334#msg367580 |
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Date |
User |
Action |
Args |
2020-04-29 00:17:06 | vstinner | set | recipients:
+ vstinner, gvanrossum, serhiy.storchaka, lys.nikolaou, pablogsal |
2020-04-29 00:17:06 | vstinner | set | messageid: <1588119426.6.0.0375929175159.issue40246@roundup.psfhosted.org> |
2020-04-29 00:17:06 | vstinner | link | issue40246 messages |
2020-04-29 00:17:06 | vstinner | create | |
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