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Author steven.daprano
Recipients mark.dickinson, serhiy.storchaka, steven.daprano
Date 2019-05-12.04:41:05
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Yes please for this!

The two usual versions are isqrt and nsqrt:

isqrt(n) = largest integer ≤ √n

nsqrt(n) = closest integer to √n

although to be honest I'm not sure what use cases there are for nsqrt.
Date User Action Args
2019-05-12 04:41:06steven.dapranosetrecipients: + steven.daprano, mark.dickinson, serhiy.storchaka
2019-05-12 04:41:05steven.dapranosetmessageid: <>
2019-05-12 04:41:05steven.dapranolinkissue36887 messages
2019-05-12 04:41:05steven.dapranocreate