Message335519
Python 3.6 no longer accept bugfixes, only security fixes:
http://devguide.python.org/#status-of-python-branches
You can try faulthandler has a workaround. For example, install faulthandler signal handler using faulthandler.register(signal.SIGUSR1) and then send a SIGUSR1 signal to the blocked process. You might want to write the output into a file if you don't have access the program stdout: use the 'file' parameter of faulthandler.register(). See also faulthandler.dump_traceback_later() to use a timeout.
https://docs.python.org/dev/library/faulthandler.html |
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Date |
User |
Action |
Args |
2019-02-14 11:42:40 | vstinner | set | recipients:
+ vstinner, lisroach, Dylan Cali |
2019-02-14 11:42:40 | vstinner | set | messageid: <1550144560.18.0.109299940711.issue35132@roundup.psfhosted.org> |
2019-02-14 11:42:40 | vstinner | link | issue35132 messages |
2019-02-14 11:42:40 | vstinner | create | |
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