you didn't understand me, look, if we put (10) in binary it will give (2)
in decimal because ((0*2**0)+(1*2**1), but it gives the tow like that 11 it
means if we add the digits in the result we will get the right result

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On Thu, 27 Dec 2018 at 18:34, Tim Peters <report@bugs.python.org> wrote:

>
> Tim Peters <tim@python.org> added the comment:
>
> `input()` returns a string, not a list.  For input '1010' you're
> effectively computing this:
>
> >>> int('1' * 8) + int('1' * 2) # = 11111111 + 11
> 11111122
>
> which is the correct answer.  If you want your input to be a list of
> integers instead of a string, try, e.g.,
>
> a = input("please enter a binary integer ")
> a = list(map(int, a))
>
> ----------
> nosy: +tim.peters
> resolution:  -> not a bug
> stage:  -> resolved
> status: open -> closed
>
> _______________________________________
> Python tracker <report@bugs.python.org>
> <https://bugs.python.org/issue35597>
> _______________________________________
>