Message306831
> Remind me what happens when you use `await` in a generator expression that survives the async function's scope?
Awaiting on f([1, 2]) will result in an async generator (even though yield never appears here). Yury explained why this happens in https://bugs.python.org/issue32113 |
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2017-11-23 16:26:26 | levkivskyi | set | recipients:
+ levkivskyi, gvanrossum, arigo, georg.brandl, rhettinger, ncoghlan, belopolsky, benjamin.peterson, erickt, glyph, Inyeol.Lee, serhiy.storchaka, yselivanov, esc24, danielsh, emptysquare, Jim Fasarakis-Hilliard |
2017-11-23 16:26:26 | levkivskyi | set | messageid: <1511454386.24.0.213398074469.issue10544@psf.upfronthosting.co.za> |
2017-11-23 16:26:26 | levkivskyi | link | issue10544 messages |
2017-11-23 16:26:26 | levkivskyi | create | |
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