Author kyoshidajp
Recipients kyoshidajp
Date 2017-11-20.13:08:43
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Message-id <1511183323.28.0.213398074469.issue32083@psf.upfronthosting.co.za>
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My schema of sqlite3 table is the following.

--- schema check start ---
% sqlite3 sample.db
SQLite version 3.16.0 2016-11-04 19:09:39
Enter ".help" for usage hints.
sqlite> PRAGMA table_info(Employees);
0|EmployeeID|int|1||1
1|LastName|varchar(20)|1||0
2|FirstName|varchar(10)|1||0

(ommiting)

sqlite>
--- schema check end ---

Then, I tried to output column types by calling Cursor.description. Like this.

--- sample code start ---
import sqlite3

con = sqlite3.connect("sample.db", detect_types=sqlite3.PARSE_DECLTYPES)
cursor = con.cursor()
cursor.execute("select LastName, FirstName from Employees limit 1;")
print cursor.description
cursor.close()
con.close()
--- sample code end ---

The output is the following.

(('LastName', None, None, None, None, None, None), ('FirstName', None, None, None, None, None, None))

When changing detect_types parameter to

detect_types=sqlite3.PARSE_DECLTYPES|sqlite3.PARSE_COLNAMES

the result is same.

I expect to output a column type in second element. Could you tell me why?
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Date User Action Args
2017-11-20 13:08:43kyoshidajpsetrecipients: + kyoshidajp
2017-11-20 13:08:43kyoshidajpsetmessageid: <1511183323.28.0.213398074469.issue32083@psf.upfronthosting.co.za>
2017-11-20 13:08:43kyoshidajplinkissue32083 messages
2017-11-20 13:08:43kyoshidajpcreate