Message271577
https://docs.python.org/3/reference/expressions.html#yield-expressions says
"When yield from <expr> is used, it treats the supplied expression
as a subiterator. All values produced by that subiterator ...".
To me "treats..expression as a subiterator" means that the expression must *be* an iterator, such as returned by iter or calling a generator function. Hence I was surprised upon reading "yield from <non-iterator iterable>" in stdlib code.
I confirmed that this usage is correct by trying
>>> def g():
yield from (1,2)
>>> i = g()
>>> next(i), next(i)
(1, 2)
and then reading the PEP380 Formal Semantics, which begins with "_i = iter(EXPR)". Hence I suggest the following replacement for the quote above:
"When yield from <expr> is used, the expression must be an iterable.
A subiterator is obtained with iter(<expr>). All values produced
by that subiterator ...".
Note that 'subiterator' is spelled in the following sentences 'underlying iterable' (which I am not sure I like) and 'sub-iterator' (and 'sub-generator'). I think we should be consistent for at least the two short 'yield from' paragraphs. |
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Date |
User |
Action |
Args |
2016-07-28 18:30:50 | terry.reedy | set | recipients:
+ terry.reedy, docs@python |
2016-07-28 18:30:50 | terry.reedy | set | messageid: <1469730650.89.0.176012351897.issue27646@psf.upfronthosting.co.za> |
2016-07-28 18:30:50 | terry.reedy | link | issue27646 messages |
2016-07-28 18:30:50 | terry.reedy | create | |
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