Author smst
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Date 2004-04-27.11:45:24
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I'll repeat the tuple hashing algorithm in a fixed-width
font (with the first line following "for..." being the loop
body):

 # assume 'my_mul' would multiply two numbers and
return the low 32 bits
value = seed
for item in tpl:
    value = my_mul(const, value) ^ hash(item)
value = value ^ len(tpl)
History
Date User Action Args
2007-08-23 14:21:12adminlinkissue942952 messages
2007-08-23 14:21:12admincreate