Message152586
This should answer that question:
>>> re.findall(r"[\A\C]", r"\AC")
['C']
>>> regex.findall(r"[\A\C]", r"\AC")
['A', 'C']
The behaviour of regex is intended to match that of re for backwards compatibility. |
|
Date |
User |
Action |
Args |
2012-02-04 03:08:52 | mrabarnett | set | recipients:
+ mrabarnett, georg.brandl, terry.reedy, jcea, sjmachin, ezio.melotti, docs@python |
2012-02-04 03:08:52 | mrabarnett | set | messageid: <1328324932.36.0.327062416186.issue13899@psf.upfronthosting.co.za> |
2012-02-04 03:08:51 | mrabarnett | link | issue13899 messages |
2012-02-04 03:08:51 | mrabarnett | create | |
|