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Author mrabarnett
Recipients docs@python, ezio.melotti, georg.brandl, jcea, mrabarnett, sjmachin, terry.reedy
Date 2012-02-04.03:08:51
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Message-id <1328324932.36.0.327062416186.issue13899@psf.upfronthosting.co.za>
In-reply-to
Content
This should answer that question:

>>> re.findall(r"[\A\C]", r"\AC")
['C']
>>> regex.findall(r"[\A\C]", r"\AC")
['A', 'C']

The behaviour of regex is intended to match that of re for backwards compatibility.
History
Date User Action Args
2012-02-04 03:08:52mrabarnettsetrecipients: + mrabarnett, georg.brandl, terry.reedy, jcea, sjmachin, ezio.melotti, docs@python
2012-02-04 03:08:52mrabarnettsetmessageid: <1328324932.36.0.327062416186.issue13899@psf.upfronthosting.co.za>
2012-02-04 03:08:51mrabarnettlinkissue13899 messages
2012-02-04 03:08:51mrabarnettcreate