Strange behavior is found when lambda is used inside for-loop.

code:(same as attached file)

# begin of CODE
def aa(x):
    print("aa")
def bb(x):
    print("bb")

namefun = [
    ("a", aa),
    ("b", bb),
]
name2fun = {}
for name, fun in namefun:
    name2fun[name] = lambda x: fun(x)
# issue happened when calling lambda
name2fun["a"](1)
name2fun["b"](1)
# end of CODE

output:
bb
bb

expected output:
aa
bb

You are running in a typical scope issue. The local and global scope of a lambda work differently than you expect. You can work around the issue by making fun a local variable:

for name, fun in namefun:
    name2fun[name] = lambda x, fun=fun: fun(x)

See also the FAQs:

https://docs.python.org/3/faq/programming.html#why-do-lambdas-defined-in-a-loop-with-different-values-all-return-the-same-result