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Created on 2020-05-08 16:06 by ihalil95, last changed 2022-04-11 14:59 by admin. This issue is now closed.
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| File name | Uploaded | Description | Edit | |
| 2020-05-07_16-47-56-afa654f51735fad98b3a593a2ea539fd.png | ihalil95, 2020-05-08 16:06 | Code error | ||
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| URL | Status | Linked | Edit |
| PR 20004 | ihalil95, 2020-05-08 16:06 | ||
| Messages (3) | |||
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| msg368450 - (view) | Author: halil ibrahim yıldırım (ihalil95) | Date: 2020-05-08 16:06 | |
While id(a[:]) and id(a[0:3]) are the same however is comparison returns False. I thought it could be a bug. >>> a = [1, 2, 3] >>> id(a[:]) == id(a[0:3]) True >>> a[:] is a[0:3] False |
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| msg368451 - (view) | Author: Eric V. Smith (eric.smith) *  |
Date: 2020-05-08 16:21 | |
This isn't doing what you think. Because you throw away the object after computing its id, the same memory is reused and you get the same id. Consider: >>> a = [1,2,3] >>> b = [3,4,5] >>> id(a[:]) == id(b[:]) True There's no problem here, but it does show that you need to be careful with "is" and "id". |
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| msg368457 - (view) | Author: Terry J. Reedy (terry.reedy) * |
Date: 2020-05-08 19:31 | |
python-list mailing list, mail.python.org, is one good place to ask "Is this a bug?" |
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| History | |||
|---|---|---|---|
| Date | User | Action | Args |
| 2022-04-11 14:59:30 | admin | set | github: 84745 |
| 2020-05-08 19:31:34 | terry.reedy | set | nosy:
+ terry.reedy messages: + msg368457 |
| 2020-05-08 16:21:11 | eric.smith | set | status: open -> closed nosy: + eric.smith messages: + msg368451 resolution: not a bug stage: resolved |
| 2020-05-08 16:06:59 | ihalil95 | create | |