----------version1：--------------
def func1():
    a=0 
    b=10
    for i in range(4):
        result = yield a+100 if b>100 else (yield a)
        print(result)

f1 = func1()
print("value:%s" % next(f1))
print("--------------")
print("value:%s" % next(f1))
print("--------------")

----------version2--------------

def func1():
    a=0 
    b=10
    for i in range(4):
        result = (yield a+100) if b>100 else (yield a)
        print(result)

f1 = func1()
print("value:%s" % next(f1))
print("--------------")
print("value:%s" % next(f1))
print("--------------")


------------------problem------------------------
I think two version should behave same,but it did not.Do this will be treated as a bug ?

Which part of the behaviour do you think is a bug?

In version1, you want to think of the yield expression as though it were bracketed like this:

    result = yield (a+100 if b>100 else (yield a))

With the particular values of a and b that you have, that statement is equivalent to this:

    result = yield (yield 0)

This yields two values to the consumer: a `0` from the inner yield, followed by a None (or whatever was "sent" into the generator, if applicable) for the out yield.

In version 2, the corresponding line simplifies to just

    result = yield 0

So no, I don't think these two versions of the code should behave the same, and I don't think there's any bug here.

Okay,I agree with you.I did not get the priority.