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Created on 2019-08-14 17:49 by f9n, last changed 2022-04-11 14:59 by admin.
| Messages (3) | |||
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| msg349726 - (view) | Author: Fatih Sarhan (f9n) | Date: 2019-08-14 17:49 | |
Same problem here. (https://bugs.python.org/issue37853) |
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| msg349728 - (view) | Author: Fatih Sarhan (f9n) | Date: 2019-08-14 17:56 | |
I just changed things and it works. But it's not right. It must be better way.(The 'urllib.parse.urlparse' function's bug should be fixed. ) https://github.com/f9n/cpython/tree/fix-issue-37854 |
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| msg349730 - (view) | Author: Sanyam Khurana (CuriousLearner) *  |
Date: 2019-08-14 18:02 | |
Closed Issue 37853 as a duplicate. Adding Fatih's comment from there for urllib.parse.urlparse ------------------------------------------------------------- No problem for these: "http://localhost:9100" "http://user:password@localhost:9100" But, these are problematic: "http://use#r:password@localhost:9100" "http://user:pass#word@localhost:9100" ``` from urllib.parse import urlparse url = "http://us#er:123@localhost:9001/RPC2" u = urlparse(url) print(u) # ParseResult(scheme='http', netloc='us', path='', params='', query='', fragment='er:123@localhost:9001/RPC2') ``` -------------------------------------- |
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| History | |||
|---|---|---|---|
| Date | User | Action | Args |
| 2022-04-11 14:59:19 | admin | set | github: 82035 |
| 2019-08-14 18:02:17 | CuriousLearner | set | nosy:
+ CuriousLearner messages: + msg349730 versions: - Python 3.5, Python 3.6 |
| 2019-08-14 17:56:58 | f9n | set | messages: + msg349728 |
| 2019-08-14 17:49:16 | f9n | create | |