In the documentation of asyncio.run_coroutine_threadsafe(coro, loop), in Section 19.5.3.6 (https://docs.python.org/3/library/asyncio-task.html#asyncio.run_coroutine_threadsafe), the example code does the following:

    future = asyncio.run_coroutine_threadsafe(coro, loop)
    # Wait for the result with an optional timeout argument
    assert future.result(timeout) == 3

 The problem is that the result method of a future, according to the documentation doesn't take parameters. It's in Section 19.5.3.4 (https://docs.python.org/3.8/library/asyncio-task.html#asyncio.Future.done)

    result()
        Return the result this future represents.


 The same function is used in Section 18.5.9.3 (https://docs.python.org/3/library/asyncio-dev.html#concurrency-and-multithreading)


 This error is present in all Python 3.* docs.

 From the asyncio source code (https://github.com/python/cpython/blob/master/Lib/asyncio/futures.py), we have this in the Future class definition:

class Future:
    """This class is *almost* compatible with concurrent.futures.Future.
    Differences:
    - This class is not thread-safe.
    - result() and exception() do not take a timeout argument and
      raise an exception when the future isn't done yet.

    ....

So this example needs to be reworked, I'd do it if I knew more about asyncio. My ideas involve either using a add_done_callback with a flag or just busy waiting until future.done().

I think `asyncio.run_coroutine_threadsafe(coro, loop)` returns a concurrent.futures.Future [1] which supports timeout and not asyncio.Future which doesn't support timeout. Please add in if I am missing anything. Since asyncio docs are being rewritten this would be a great time to contribute too if you would like to add more clarification.

Docs at [1] also say the below : 

asyncio.run_coroutine_threadsafe(coro, loop)

    Submit a coroutine to the given event loop. Thread-safe.

    Return a concurrent.futures.Future to wait for the result from another OS thread.


```
# bpo33117.py. This needs to be called from a different thread as docs said but I am using future.result(timeout) just to make sure there is no error with respect to function argument.

import asyncio

loop = asyncio.get_event_loop()
timeout = 4

# Create a coroutine
coro = asyncio.sleep(1, result=3)

# Submit the coroutine to a given loop
future = asyncio.run_coroutine_threadsafe(coro, loop)

# Wait for the result with an optional timeout argument
assert future.result(timeout) == 3
```


➜  cpython git:(master) ./python.exe bpo33117.py
Traceback (most recent call last):
  File "../bpo33117.py", line 13, in <module>
    assert future.result(timeout) == 3
  File "/Users/karthikeyansingaravelan/stuff/python/cpython/Lib/concurrent/futures/_base.py", line 438, in result
    raise TimeoutError()
concurrent.futures._base.TimeoutError

[1] https://docs.python.org/3.8/library/concurrent.futures.html#concurrent.futures.Future



Thanks

@xtreak is right, `run_coroutine_threadsafe()` returns `concurrent.futures.Future` object.

Personally, I like the fact that `fut.result()` is called with timeout parameter to reflect the fact of the different object type.