Message234767
@Joshua: Re: f(x: y for x, y in z)
I don't think that follows at all.
We support f(**d) now, but if d == {'a': 1, 'b': 2}, it is equivalent to f(a=1, b=2), not f(a: 1, b: 2). |
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Date |
User |
Action |
Args |
2015-01-26 18:41:24 | gvanrossum | set | recipients:
+ gvanrossum, twouters, georg.brandl, terry.reedy, paul.moore, ncoghlan, belopolsky, ezio.melotti, eric.araujo, andybuckley, r.david.murray, zbysz, eric.snow, berker.peksag, Joshua.Landau, pconnell, NeilGirdhar, Jeff.Kaufman, SpaghettiToastBook |
2015-01-26 18:41:24 | gvanrossum | set | messageid: <1422297684.09.0.926371162652.issue2292@psf.upfronthosting.co.za> |
2015-01-26 18:41:24 | gvanrossum | link | issue2292 messages |
2015-01-26 18:41:24 | gvanrossum | create | |
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