import io
import urllib.request

f_bytes = urllib.request.urlopen("http://www.python.org/")
f_string = io.TextIOWrapper(f_bytes, "iso-8859-1")
print(f_string.read())

Fixed in r70928.

Nope, this is not yet fixed.

$ ./python 
Python 3.1a1+ (py3k:70929, Mar 31 2009, 19:18:12) 
[GCC 4.3.2] on linux2
...
...
>>> f_bytes = urllib.request.urlopen("http://www.python.org")
>>> f_string = io.TextIOWrapper(f_bytes,"iso-8859-1")
>>> print(f_string.read())
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
IOError: not readable

urllib.response.addinfourl doesn't seem to implement the required ABC
(BufferedIOBase) properly. It misses the read1() method. Also, it claims
not to be readable:

>>> f_bytes = urllib.request.urlopen("http://www.python.org/")
>>> f_bytes.readable()
False

I just wanted to mention that the current head of py3k returns an
http.client.HTTPResponse and not a urllib.respone.addinfourl.  That
doesn't mean it is the right thing to pass to TextIOWrapper.  It's an
instance of RawIOBase.

Jeremy Hylton  wrote:
>  That doesn't mean it is the right thing to pass to TextIOWrapper.  It's an
> instance of RawIOBase.

I guess, you meant " That doesn't mean it is *not* the right thing to
pass to TextIOWrapper".

With the changes r70935, this works.

Please note that passing a instance of RawIOBase (as HTTPResponse) is
to TextIOWrapper is *not* supported. You must first wrap the raw IO in
a BufferIOBase instance.

I suppose it is fixed, isn't it?

Yes