struct.calcsize('cd') returns 16 instead of 9

struct.calcsize('dc') returns 9 as expected

Someone pointed out that one must consider alignment. I had overlooked
that. It makes sense that a d is double-word aligned.

Perhaps the documentation should mention alignment.

The docs have this sentence:

"""
By default, C numbers are represented in the machine's native format and
byte
order, and properly aligned by skipping pad bytes if necessary
(according to the
rules used by the C compiler).
"""

What would you suggest be added?

The default endiand and alignment is "native". Using <, >, = or ! 
endian, the alignement is standard.

Python 3.1a0 (py3k:69105M, Feb  3 2009, 15:04:35)
>>> struct.calcsize('cd')
12
>>> struct.calcsize('=cd')
9
>>> struct.calcsize('<cd')
9

Sorry, but I don't see this issue as a bug because it's related to 
memory alignment as explained in the documentation. 

I choose to close this issue. If you think that the documentation 
should be improved, please suggest an updated doc.
http://docs.python.org/library/struct.html#struct.calcsize