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Created on 2008-08-18 12:02 by misha, last changed 2022-04-11 14:56 by admin. This issue is now closed.
| Messages (2) | |||
|---|---|---|---|
| msg71323 - (view) | Author: Misha Seltzer (misha) | Date: 2008-08-18 12:02 | |
import re
regex = r"[\w]+"
# Normal behaviour:
>>> re.findall(regex, "hello world", re.M)
['hello', 'world']
>>> re.compile(regex).findall("hello world")
['hello', 'world']
# Bug behaviour:
>>> re.compile(regex).findall("hello world", re.M)
['rld']
|
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| msg71326 - (view) | Author: Antoine Pitrou (pitrou) *  |
Date: 2008-08-18 13:25 | |
The re.M flag is an attribute of the compiled pattern, and as such it
must be passed to compile(), not to findall().
These all work:
>>> re.compile(r"[a-z]+").findall("hello world")
['hello', 'world']
>>> re.compile(r"[a-z]+", re.M).findall("hello world")
['hello', 'world']
>>> re.compile(r"(?m)[a-z]+").findall("hello world")
['hello', 'world']
The second argument to the findall() method of compile objects is the
start position to match from (see
http://docs.python.org/lib/re-objects.html). This explains the behaviour
you are witnessing:
>>> re.M
8
>>> re.compile(r"[a-z]+").findall("hello world", 8)
['rld']
|
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| History | |||
|---|---|---|---|
| Date | User | Action | Args |
| 2022-04-11 14:56:37 | admin | set | github: 47837 |
| 2008-08-18 13:25:09 | pitrou | set | status: open -> closed resolution: not a bug messages: + msg71326 nosy: + pitrou |
| 2008-08-18 12:02:22 | misha | create | |