https://docs.python.org/3/library/argparse.html#argumentparser-objects
"prog - The name of the program (default: sys.argv[0])"

It doesn't take all sys.argv[0]. It splits sys.argv[0] and takes only the trailing part.

An example:

a.py

#!/usr/bin/env python3

import argparse
import sys

parser = argparse.ArgumentParser()
parser.add_argument("arg", help="The name is %(prog)s, the sys.argv[0] is " + sys.argv[0])
args = parser.parse_args()


The output in the console:

[guest@localhost bugs]$ ../bugs/a.py -h
usage: a.py [-h] arg

positional arguments:
  arg         The name is a.py and sys.argv[0] is ../bugs/a.py

optional arguments:
  -h, --help  show this help message and exit
[guest@localhost bugs]$


In the output we see that %(prog)s takes only trailing part of sys.argv[0] not all.

Applied a patch to the issue that specifies about part of sys.argv[0].

Thanks for the report. To be little more clear it returns the "basename of sys.argv[0]" at [0] than the attached patch that says "uses part of ``sys.argv[0]``" .

[0] https://github.com/python/cpython/blob/62f9588663ebfea1735e9d142ef527395a6c2b95/Lib/argparse.py#L1638

@Karthikeyan Singaravelan
Thank you for the point. I added a new patch.

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