Int to decimal string conversion (function long_to_decimal_string_internal() at Objects/longobject.c:1583) has a limitation. On 32-bit platform you can't convert integers larger than 2**2**31 (10**646456993). Proposed patch removes this limitation [*].

It also decreases memory requirements for intermediate buffer on 10%. The size of intermediate buffer (in digits) depends on the size of the integer. Unpatched:

For 15-bit digits: size*15/4/3 = size*1.25
For 30-bit digits: size*30/9/3 = size*1.11

Patched:
For 15-bit digits: size*15/4/3.3 = size*1.14
For 30-bit digits: size*30/9/3.3 = size*1.01


[*] Converting such large integers to decimal string can be not finished for reasonable time, because it has quadratic complexity. On my netbook the estimated time of calculating str(2**2**31) is 5 years. But this is different issue.

Currently, the code uses Py_ABS(Py_SIZE(x))*PyLong_SHIFT to estimate the upper-bound of the number of bits of the number x. It's a raw estimation, the difference can be up to 29 bits. We may try to compute the exact number of bits, x.bit_length().

Python 3.5 estimate the number of "decimalbase" (10**9) digits using:

def decimalbase_digits1(x):
    bits = size(x) * PyLong_SHIFT
    return 1 + bits // (3 * _PyLong_DECIMAL_SHIFT)

I wrote a test to compute how many digits are overallocated (and unused): 552961 for this function. I'm not sure that "1+" is needed, since 3.0 is already lower than log2(10) (3.32...). If we compute the exact number of bits using the Python 3.5 function, it's a little bit better:

def decimalbase_digits2(x):
    bits = x.bit_length()
    return 1 + bits // (3 * _PyLong_DECIMAL_SHIFT)

=> 546250 digits (1% less). You propose a better estimation:

def decimalbase_digits3(x):
    digits = size(x)
    d = (33 * _PyLong_DECIMAL_SHIFT) // (10 * PyLong_SHIFT - 33 * _PyLong_DECIMAL_SHIFT)
    return 1 + digits + digits // d

With your estimation, only 504243 are overallocated (9% less than Python 3.5 function). But why only using 2 digits for log2(10) estimation? We can more digits:

def decimalbase_digits4(x):
    bits = size(x) * PyLong_SHIFT
    return bits * 10000 // (33219 * _PyLong_DECIMAL_SHIFT)

=> 491908 digits (11% less)

According to my tests, the best function uses the number of bits and the better estimation of log2(10):

def new_decimalbase_digits5(x):
    bits = x.bit_length()
    return bits * 10000 // (33219 * _PyLong_DECIMAL_SHIFT)

=> 483424 digits (13% less)


See attached for my tests.

> But why only using 2 digits for log2(10) estimation?

Because the difference between 3 and 3.3 is 10%, and the difference between 3.3 and exact log2(10) is only 1%. Yes, we can use more digits, but the effect of any additional digit is decreased in geometric progression.

If use simple and fast formula that avoids integer multiplication overflow "digits + digits // d", the effect of additional precision is virtually vanished.

>>> PyLong_SHIFT, _PyLong_DECIMAL_SHIFT = 15, 4
>>> (3 * _PyLong_DECIMAL_SHIFT) // (1 * PyLong_SHIFT - 3 * _PyLong_DECIMAL_SHIFT)
4
>>> (33 * _PyLong_DECIMAL_SHIFT) // (10 * PyLong_SHIFT - 33 * _PyLong_DECIMAL_SHIFT)
7
>>> (33219 * _PyLong_DECIMAL_SHIFT) // (10000 * PyLong_SHIFT - 33219 * _PyLong_DECIMAL_SHIFT)
7

>>> PyLong_SHIFT, _PyLong_DECIMAL_SHIFT = 30, 9
>>> (3 * _PyLong_DECIMAL_SHIFT) // (1 * PyLong_SHIFT - 3 * _PyLong_DECIMAL_SHIFT)
9
>>> (33 * _PyLong_DECIMAL_SHIFT) // (10 * PyLong_SHIFT - 33 * _PyLong_DECIMAL_SHIFT)
99
>>> (332 * _PyLong_DECIMAL_SHIFT) // (100 * PyLong_SHIFT - 332 * _PyLong_DECIMAL_SHIFT)
249
>>> (3321 * _PyLong_DECIMAL_SHIFT) // (1000 * PyLong_SHIFT - 3321 * _PyLong_DECIMAL_SHIFT)
269
>>> (33219 * _PyLong_DECIMAL_SHIFT) // (10000 * PyLong_SHIFT - 33219 * _PyLong_DECIMAL_SHIFT)
290
>>> (332192 * _PyLong_DECIMAL_SHIFT) // (100000 * PyLong_SHIFT - 332192 * _PyLong_DECIMAL_SHIFT)
291
>>> (332192809 * _PyLong_DECIMAL_SHIFT) // (100000000 * PyLong_SHIFT - 332192809 * _PyLong_DECIMAL_SHIFT)
291

The best approximation with minimal denominator is 485/146.

>>> PyLong_SHIFT, _PyLong_DECIMAL_SHIFT = 15, 4
>>> (485 * _PyLong_DECIMAL_SHIFT) // (146 * PyLong_SHIFT - 485 * _PyLong_DECIMAL_SHIFT)
7
>>> PyLong_SHIFT, _PyLong_DECIMAL_SHIFT = 30, 9
>>> (485 * _PyLong_DECIMAL_SHIFT) // (146 * PyLong_SHIFT - 485 * _PyLong_DECIMAL_SHIFT)
291

New changeset 1902e1d79e25 by Mark Dickinson in branch 'default':
Issue #25402: in int-to-decimal-string conversion, reduce intermediate storage requirements and relax restriction on converting large integers. Patch by Serhiy Storchaka.
https://hg.python.org/cpython/rev/1902e1d79e25

Patch and analysis LGTM. Thanks!