The following two expressions should have the same value:

Python 3.4.0a0 (default:fae92309c3be, Jun 14 2013, 09:29:54) 
[GCC 4.8.0] on linux
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>>> 1 in [2] == False
False
>>> (1 in [2]) == False
True


It looks like this is a compiler issue - there shouldn't be a jump if the 'in' expression is false:

>>> dis.dis("1 in [2] == False")
  1           0 LOAD_CONST               0 (1)
              3 LOAD_CONST               1 (2)
              6 BUILD_LIST               1
              9 DUP_TOP             
             10 ROT_THREE           
             11 COMPARE_OP               6 (in)
             14 JUMP_IF_FALSE_OR_POP    24
             17 LOAD_CONST               2 (False)
             20 COMPARE_OP               2 (==)
             23 RETURN_VALUE        
        >>   24 ROT_TWO             
             25 POP_TOP             
             26 RETURN_VALUE        
>>>

This is one case of chained comparisons:
http://docs.python.org/3/reference/expressions.html#not-in

"x <= y <= z" is equivalent to "(x <= y) and (y <= z)"
"x in y == z" is equivalent to "(x in y) and (y == z)"

There is a jump if the 'in' expression is false, because 'and' should short-circuit the second comparison.

Thanks Amaury. That's quite surprising, but I wouldn't advocate changing such long standing behaviour.

I'm closing the issue.