print datetime.time(hour=0)+datetime.timedelta(hours=1) 

...gives...

TypeError: unsupported operand type(s) for +:
'datetime.time' and 'datetime.timedelta'

Which is a bit frustrating :-/

Does it really need to be this way?

Chris

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Since the lack of arithmetic on `time` objects is both
intended and documented, this isn't "a bug".  I moved this
to the Feature Requests tracker.

The problem with arithmetic on time objects is that it's not
obvious what to do in case of overflow or underflow:  wrap
around or raise OverflowError?  Either way violates _some_
reasonable expectation.  Embed your time in a `datetime`
object and then you can decide what you want to do.  For
example, if you want to wrap around,

>>> print (datetime.combine(date.today(), time(hour=0)) -
timedelta(hours=1)).time()
23:00:00

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Well, I think the OverflowError is perfectly correct, and
lets the software author handle that situation in any way
they want.

That said, you could add a keyword option to the
datetime.time constructor to allow it either to wrap round,
or raise OverflowError, with the overflow being the default.

If I resulted up patches for these, how would I get them
into a python release?

See this other issue I just closed:

    http://bugs.python.org/issue1118748